$12:-8$
$\left(3x^2+2y^3-1\right)^2$
$\ln\left(x+2\right)+\ln\left(x-1\right)=\ln\left(4x+2\right)$
$24-5\cdot3$
$\left(4^f-3a\right)^3$
$\left|-7+\left(-1\right)+7\right|$
$\left(\frac{x^3-8}{2x^2+4x+8}\right)$
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