$\left(x+8\right)^2=x^2+8x+16$
$\frac{125}{\frac{\left(-5\right)}{5}}$
$2+5+3+6+7.2$
$4\:\left(5x^4-5x^2\:+\:4\right)$
$5x^2+25x+20$
$\left(-9x\right)\left(-x+5\right)$
$\left(x^2+a^2\right)\left(x^2+b^2\right)$
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