$\lim_{x\to\infty}\left(\sqrt{9x^2+7}-3x\right)$
$\left(+3\right)-\:\left(+5\right)-\:\left(-9\right)+\left(-23\right)+\left(+4\right)$
$9x^4-16y^2$
$\frac{2x^3-5x^2+6x-3}{x+2}$
$f\left(x\right)=\left(5x^3-x^2+1\right)\left(3x^2-2x-1\right)$
$\left(v-4\right)\left(v+1\right)$
$25 = 7 + v$
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