$\lim_{x\to4}3x+5$
$16a^2+24ab+96b^2$
$-2\cdot39$
$-4m-2\frac{1}{4}-6\frac{1}{4}$
$128x^2-54$
$\left(-6\right)\left(-5\right)\left(-3\right)\left(4\right)\left(-3\right)\left(-5\right)$
$y'-\frac{6x}{5y^2}=0$
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