$2x^4-4x$
$4x^2-12x-9$
$\left(-2\right)^2-1$
$y'=y-x$
$\left(-5\right)\left(-5\right)\left(-3\right)$
$\left(5a-\frac{2}{3}\right)^2$
$\int\frac{3x+6}{\left(6x^2+28x-160\right)}dx$
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