$\lim_{x\to-2}\left(\frac{x^2+4x+4}{x^2-5}\right)$
$\int x^3\cdot sqrt\left(4-x^2\right)dx$
$2x\:-\:5\:<\:3x\:-\:6$
$x+4=8$
$\frac{dy}{dx}=\frac{5y^2}{x}$
$2y^2-6y=0$
$tan^2x\:-\:tanx-2=0$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!