$\int_1^{e^x}\:\frac{in\sqrt{t}}{\sqrt{t}}\:dt$
$5=x^2-4$
$\int_0^{70}\left(22x\right)dx$
$\frac{x^2-6x+4}{x^2}$
$\lim_{x\to0}\left(\frac{2x^2-x}{x}\right)$
$\left(-3\right):\left(3\right).\left(-3\right)$
$8x-4=13x+6$
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