$y=\frac{6}{x-1}\:3,3$
$\left(7x^3+6x^2+9x\right)+\left(-8x^3-9x^2-6x\right)+\left(4x^3-18x^2+9x\right)$
$\frac{18^0}{18^{-2}}$
$\frac{d}{dx}t\sqrt{10}$
$\left(9.67\cdot10^6\right)+\left(3.45\cdot10^5\right)$
$2x+3<x-1$
$\left(3x^3+5\right)\left(3x^3-5\right)$
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