$2^3x\:2^2$
$\frac{dx}{dt}+sin\left(t\right)x=0$
$2x^2+9x-4=9$
$\frac{dy}{dx}=\frac{lnx}{xy};\:y\left(1\right)=2$
$-18\cdot18$
$2x^2+5x+4=0$
$\sqrt{5}+5\sqrt{5}$
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