$\int\frac{\left(x-5\right)}{\left(2x+3\right)^2}dx$
$\frac{d}{dx}\left(x^x\right)\:y=x^{8\cos\left(x\right)}$
$y^{12}+125$
$9x^2+4y^2-36x\:+8y=-4$
$\left(\frac{\tau}{9}+\frac{t}{6}\right)\left(\frac{\tau}{9}-\frac{t}{5}\right)$
$\int_{0.05}^{0.08}\left(\frac{3500}{3}\right)x\:dx$
$\frac{1-\tan^{2}\alpha}{1+\tan^{2}\alpha}=\cos^{2}\alpha-\sen^{2}\alpha$
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