$\sin^2\left(\arccos\left(x\right)\right)$
$6x=4x^2-1$
$\lim_{x\to\infty}\left(\frac{3x+1}{3x-1}\right)^{6x}$
$3a+2b+a-3b$
$\left(\frac{2x^2+7x-4}{4x-2}\right)$
$\frac{dy}{dx}=16e^{8x}y^2+81e^{8x}$
$4-c=-12$
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