$\frac{d^3}{dx^3}\left(\frac{1-x}{1+x}\right)$
$6\cdot\left(-6\right)\cdot\left(4\right)$
$\left(x-7\right)\left(x+49\right)$
$\left(\frac{3}{5}\right)^2+2\frac{3}{5}x\frac{5}{7}+\left(\frac{5}{7}\right)^2$
$3x+1<5x-4$
$2x+5y-3x-7z+12y-6z$
$2\left(x+6y\right)$
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