$-4x+3\left(x-1\right)+2=5$
$\frac{x^4}{8-x^3}$
$3x^2-4\ge\:5$
$\int\left(\frac{40}{\left(120-x\right)}\right)dx$
$\frac{a^2-2a-3}{a+3}$
$\left(9ab^2+5a^2\:b^3\:\right)^2$
$16\:sin\left(4x\right)cos\left(4x\right)cos\left(8x\right)$
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