$2x^28$

$\frac{\left(4x^{2\:}\right)}{\left(3+4x^3\right)^2}$

$\lim_{x\to-2}\left(x\sqrt{x+4}\sqrt[3]{x-6}\right)$

$x^3+4^2-3x+8$

$\tan^3\left(x+1\right)=\left(\tan\left(x+1\right)\right)\left(\sec^2\left(x\right)-\tan\left(x\right)\right)$

$\frac{dy}{dx}-2y=4-t$

$\int_{-\infty}^{-1}\left(e^{-2t}\right)dt$