$\frac{1}{\sin}+\frac{1}{\tan}$
$\lim_{x\to\infty}\left(tan\left(hx\right)\right)$
$\frac{dy}{dx}=\frac{\left(2-x\right)}{y}$
$\sin\left(xy\right)=x^3$
$\left(3x+7yz^4\right)\left(-3x+7yz^4\right)$
$\int p\left(p+1\right)^4dp$
$-7+4^2$
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