$\left(2\right)^3-3\left(-2\right)^2-4\left(2\right)-30$
$\left(5^27^6\right)^3$
$-17>\frac{x}{3}-19$
$\frac{d}{dx}9\arctan\left(x-\sqrt{1+x^2}\right)$
$\left(4\right)\left(-2\right)\left(-5\right)\left(-12\right)$
$\frac{4b^{-3}}{5a^{-5}}$
$-7x+5<2x-10$
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