$16x^2-72x+81$
$\frac{y}{2}+6=24$
$\int\left(\frac{6x-3}{\left(x+1\right)\left(x^2+4\right)}\right)dx$
$\frac{0.9}{0.1}$
$\int\frac{\left(x^2+2\right)}{\left(x+1\right)}dx$
$-x^3+x^2+48$
$\left[\left(7^5\right)\left(7^3\right)\right]^{-4}$
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