$49\cdot16$
$\frac{d}{dx}\left(\left(3x-2x^2\right)^7\right)$
$-9+6-\left(-28\right)-10$
$\int\left(\frac{1}{\left(6x+8\right)^3}\right)dx$
$1-9x^2$
$1+\sin\left(x\right)=\frac{3}{2}$
$16^6-8x^3$
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