$\left(4f^5\right)^2$
$f\cdoty=\frac{2x^{2}-x}{x-1}$
$x^3-3^2-2x+1$
$\sin\left(x\right)^2+5\cos\left(x\right)=1$
$\left(1-t^2\right)\frac{dx}{dt}+4tx=t$
$\lim_{x\to\infty}\left(\frac{2x^2+4x+3}{x^2-1}\right)$
$\frac{3x^3+2x^2-3x-2}{x^2-1}$
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