$27a^3-64b^6$
$\frac{-2+n}{12}=1$
$-176-80$
$\left(-2\right)\left(-3\:\left(-28\right)\right)$
$\frac{\left(27a^3+8b^3\right)}{\left(9a^2+4b^2\right)}$
$\frac{12}{20}-\frac{12}{20}$
$-2x+6;x=1,x=4$
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