$\lim_{x\to\infty}\left(\frac{3x-4}{\sqrt{x^2+5}}\right)$
$4x^2-16x-3$
$\left(+135\right).15$
$3y^2-4y-4$
$3.5y+2.25y=345$
$8\:\ln x-\frac{1}{9}\ln y$
$x^2y-xy-8;\:x=-1;\:y=2$
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