$b\left(8\right)=-16\left(8-4\right)^2+256$

$-76\left(-61\right)+\left(-13\right)-\left(-4+\left(-6\right)\right)$

$\int\frac{3x^2}{x^2+x-6}dx$

$\frac{d}{dx}y=\sqrt[3]{x}+\frac{1}{\sqrt[3]{x}}$

$x+15<11$

$\left(2\sqrt{a}+\sqrt[3]{b}\right)\left(2\sqrt{a}-\sqrt[3]{b}\right)$

$2y^2+4y+4$