$2^{10x-10}=2^{30}$
$\frac{2x^2+3}{5}\ge\:\frac{12+3x}{6}$
$\log0.01=x$
$2\:\left(\:x\:-\:12\right)\:=\:x\:+\:18$
$-x=0$
$-a-a$
$\left(\frac{3}{4}a^{5x}b^{2m}-\frac{9}{2}\right)\left(\frac{8}{15}a^{5x}b^{2m}-\frac{16}{9}\right)$
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