$x^2+7x+10\cdot x+3$
$\left(2ab-c\right)\left(ab+4c\right)$
$-6+\left(-5\right)\cdot\left(-8\right)-\left(5-\left(-2\right)\right)\cdot\left(-7\right)$
$\frac{t^3+z^3}{t+z}$
$x^2-4x+8=0$
$\left(5^3\right)^8$
$\int10cos\left(6t\right)sin^2\left(6t\right)dt$
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