$\int\:6xe^{3x}dx$

$-5xy^3\left(2x^3-x^2-6\right)$

$\frac{\left(4x^6-4\right)}{\left(x-1\right)^2\left(x+1\right)^2\left(x^2+x+1\right)}$

$f\left(x\right)=7\left(x^{3}-4\right)^{2}$

$-2+6w=10$

$1-4b+4b^2$

$\frac{d}{dx}y^2+y+x=\arctan^2\left(\sin^2\left(x\right)\right)$