$-78.5-39.5$

$\lim_{x\to0}\left(\frac{sin2x-tan2x}{x^3}\right)^2$

$500cm^3\cdot1cm$

$\int\left(\frac{3x}{2-6x^2}\right)dx$

$\left(6p-3q\right)\left(6p+4s\right)$

$\cos\left(x\right)^2\left(1-\tan\left(x\right)^2\right)=\cos\left(2x\right)$

$\int\frac{2y^3+y^2+2y+2}{y^4+3y^2+2}dy$