$\frac{1}{y}y'\:=\frac{1}{x}$
$4x^4-25x^2$
$\left(e^{2x}\right)^2\left(x^2\right)^3$
$y'+2xy=8x$
$\frac{8a^3b^4}{7ab^{-2}}$
$\left(\frac{2}{3}x^2-\frac{1}{4}y^2+\frac{3}{5}xy\right)\left(2y-\frac{3}{2}x\right)$
$\left(2xy-z\right)\left(2xy-2t\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!