$\lim_{x\to9}\left(\frac{x+9}{\left(x-9\right)^6}\right)$
$x^2-x=\frac{2}{9}-\frac{2x}{3}$
$\left(5x-15\right)\left(5x+15\right)$
$\left(4x-7xy-6z\right)\cdot8$
$\int\left(\frac{\cos\left(u\right)}{3}\right)du$
$\frac{5}{2}cos\left(x\right)+4=2$
$\sqrt[3]{\frac{y^2}{y\frac{4}{5}}}$
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