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Simplify the product of radicals $\sqrt[5]{2^{10}}\sqrt{3^4}$

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 Final answer to the problem

$36$
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 Step-by-step Solution 

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• Choose an option
• Write in simplest form
• Prime Factor Decomposition
• Solve by quadratic formula (general formula)
• Find the derivative using the definition
• Simplify
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• Factor by completing the square
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1

Simplify $\sqrt[5]{2^{10}}$ using the power of a power property: $\left(a^m\right)^n=a^{m\cdot n}$. In the expression, $m$ equals $10$ and $n$ equals $\frac{1}{5}$

$2^{10\cdot \left(\frac{1}{5}\right)}\sqrt{3^4}$

Learn how to solve product of radicals problems step by step online.

$2^{10\cdot \left(\frac{1}{5}\right)}\sqrt{3^4}$

Learn how to solve product of radicals problems step by step online. Simplify the product of radicals 2^10^(1/5)3^4^(1/2). Simplify \sqrt[5]{2^{10}} using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 10 and n equals \frac{1}{5}. Multiply the fraction and term in 10\cdot \left(\frac{1}{5}\right). Divide 10 by 5. Calculate the power 2^{2}.

 Final answer to the problem

$36$

 Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

 Main Topic: Product of Radicals

The product of radicals is an expression that involves the multiplication of two or more radicals.