$2x+3<x+1$
$\frac{dx}{dt}=\left(1-x\right)\left(1-2x\right)$
$\frac{2x+1}{3}>3$
$x^4+x^3y^2$
$\frac{\left(t+9\right)}{\left(t-3\right)}<-\frac{1}{2}$
$\left(6x^4\right)\left(-6x+3y^4\right)$
$\lim_{x\to-\infty}\left(4x+\left(\sqrt{16x^2-3x}\right)-9\right)$
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