$9x^2-8x+4$
$\sqrt[5]{\frac{5x}{4x-3}}$
$\lim_{x\to+\infty}\left(\frac{3}{7}\right)x$
$\left(2x^{-2}\right)-4$
$x+3>4,1$
$\left(1+\sin\:\left(\alpha\:\right)\right)^'\left(1-\sin\:\left(\alpha\:\right)\right)^'=\frac{1}{\sec\:^2\left(\alpha\:\right)}$
$\frac{-3n^2+6n}{3n}$
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