$\left(10x^6+4x^4\right)-\left(6x^6-8x^4\right)$
$4x+3+x^2-x$
$10^2\cdot7$
$\left(18\right)\left(4\right)+\left(18\right)\left(-2\right)\left(11\right)$
$-2\sec\left(x\right)+6=-10\sec\left(x\right)-10$
$32-19+43-18+35-53$
$\frac{x^4-16}{x^3-8}$
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