$4\left(x+1\right)-6x>-4$
$2\sin^2\left(30\right)+3\sin\left(30\right)+5$
$2,23+3$
$.058\cdot10^4$
$\int\frac{\left(sec^2x\right)}{\sqrt{16-tan^2x}}dx$
$\left(2xy-3\right)^2+\left(2x-4\right)\cdot\left(2x-6\right)$
$\left(7xy+1\right)\left(2xy-3\right)$
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