$\frac{d}{dx}\left(3x^4-2x^3+x^2\right)$
$-126:\left(-6\right)-\left(-13+32\right)$
$\frac{6x^3}{3+2x^2}$
$\lim_{x\to\infty}\left(\frac{ln\left(10x+6\right)}{ln\left(6x+5\right)+4}\right)$
$012+009+019+009+006+025+016$
$16^{2^{-1}}$
$\frac{3}{1}+\frac{3}{1}$
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