$\left(\sqrt{a}-\sqrt{x}\right)\left(\sqrt{a}-\sqrt{x}\right)$
$\lim_{x\to\infty}\left(\frac{2lnx+1}{4x^2}\right)$
$4\left(g+4\right)$
$\left(x+2\right)^3\:\left(x-2\right)^3$
$x+8<5$
$\frac{x^2-9}{2x+4}$
$123+1.23+3.12+31.2+12.3+23.1+2.31+3+2.13+12$
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