$1-\cos^2x=\frac{\sin x\cos x}{\cot x}$
$1.6k=3.2$
$y'\:-\:y^2\:-\:y\:=\:0$
$\frac{1+cos\left(x\right)}{1+sec\left(x\right)}=cos\left(x\right)$
$+43+2$
$\int\left(x^3+5x^2\right)cos4xdx$
$10^2+20x+4$
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