$9x^2-30x+6$
$2x^2\:-4$
$6\left(3a\right)^1\left(4b^2\right)^5$
$4+3\cdot5\cdot\left(2+3\right)-7+4\left(1-3\right)$
$\lim_{x\to0}\ln\left(1+3x^5\right)$
$\frac{x^2}{x-2}$
$n\left(n-2\right)\left(n+2\right)=n^3-4n$
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