$x^6-x^3+\frac{1}{8}x^3$
$12x\:+\:24y$
$\int sen^3\:4x\:dx$
$\frac{dy}{dx}=\frac{-x+2y}{4x+y}$
$e^{-y}\frac{dy}{dx}=\frac{1}{\sqrt{x^2+1}}$
$\left(15\right)\cdot\left(79-48\right)$
$\int\frac{x}{\left(x^2+a^2\right)^{\frac{3}{2}}}dx$
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