$\:\sqrt{\frac{x^2+4x+4}{x^2-4}}$
$\int x^3\sqrt{16-4x^2}dx$
$-10+3x<10$
$4\sqrt{8}$
$\lim\:_{t\to\:0}\left(\frac{\left(\left(6t^2-24t+36\right)\cdot\:e^t-12t+36\right)}{t^4}\right)$
$cot\left(90-\theta\right)=tan\:\theta$
$\left(-5+3\right)^2+\left(1+3\right)^2$
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