$-5\left(4y+6\right)+4\left(3y-4\right)$
$8-28-\left(-2\right)+10$
$\log\left(\frac{10}{10m}\right)$
$\left(+54\right)\cdot\left(+11\right)$
$\frac { 1 } { 3 x ^ { 2 } + x }$
$\frac{m^3+8}{m+2}$
$\int\tan^5\left(x\right)\frac{1}{\sec^2\left(x\right)}dx$
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