$\lim_{x\to-1}\left(\frac{x^2+x}{x+1}\right)$
$\frac{x+12}{x^2-144}$
$6a^2+6b^2$
$2\left(7\right)+4\left(9\right)$
$1000+200x\ge1800+110x$
$\frac{246.8}{8}$
$\left(2a-5\right)\left(a+3\right)$
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