$\frac{\cos x+\cos\left(x\right)\cdot\tan^2\left(x\right)}{\sec^2\left(x\right)}=\cos\left(x\right)$
$3\left(2x-2\right)=2\left(3x+9\right)$
$\frac{du}{dx}=\sqrt{x}-4$
$x^2-4\ge2x+4$
$\frac{b}{7}^4$
$-\:\left(-n\:+\:2\right)\:-\:2n$
$\sin\left(2x\right)\sec^2\left(x\right)$
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