$10.9+8.5+9.8+1.5+3.5$
$\frac{x+1}{x+2}+\frac{x-8}{x-9}$
$3x^2-8x=11$
$\int_{-4}^6\left(\frac{1}{x^2-6x+9}\right)dx$
$2\left(3-1\right)+5\left(2\right)$
$\left(2+7\sqrt{7}\right)\left(2-7\sqrt{7}\right)$
$10x\le-9$
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