$\frac{x+1}{x-2}=\frac{x-3}{x}$
$10+\left|-9-\left(15-11\right)+5\right|$
$\left(6m\:-\:23\right)\:\left(6m\:+\:23\right)$
$-10x^2+7x+25\le0$
$6x+5>4x+11$
$3p^3+6p$
$t^3-5t^2+10-2t$
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