$\left(11x+4y\right)^2$
$\frac{29}{1}$
$n.8n=392$
$\frac{x+2}{3}>\frac{2\left(x-4\right)}{3}$
$6\ln\left(x+9\right)-7\ln\left(x\right)$
$x^2-32x+256=0$
$6x<12$
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