$\int16x^{-3}dx$
$10x^2+24x-130$
$16x^2+72xyw$
$c=\left(x+5\right)^2+\left(x-5\right)^2$
$\int\sin13\:x\:dx$
$64-9x^2$
$\left(7a^5b^6+4c\right)\left(7a^5b^6-9c\right)$
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