$8-x=x+4$
$\lim_{x\to\infty}\left(1+\frac{2}{x}\right)^{x+2}$
$-1m+9>4$
$-5x+3x-8x+5x+10x$
$5^2+20x+4$
$\left(a^{10}\right)^2$
$\left(\frac{1}{4}x\:+\:\frac{1}{5}\right)\left(\frac{1}{4}x-\frac{5}{3}\right)$
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