$-\frac{1}{3}x\:+\frac{1}{2}y\:+\frac{3}{8}-3y+2x-\frac{1}{6}y-\frac{3}{4}x-\frac{1}{2}$

$\sqrt{3}\tan\left(\frac{1}{3}x\right)=1$

$\frac{sen\left(x\right)+\frac{cos\left(x\right)}{sen\left(x\right)}}{\frac{1}{sen\left(x\right)}+\frac{sen\left(x\right)}{cos\left(x\right)}}=cos\left(x\right)$

$6\:+\:\frac{4}{2}$

$\int_a^{2a}\left(2a-x\right)^2dx$

$\left(x^{3+y^3}\right)dx-xy^2dy=0$

$x+9=3x+21$