$\frac{3-3x}{2}<-3$
$\frac{5x^4+9}{x}$
$\lim_{x\to0}\left(\frac{\frac{1}{2}-\cos\left(\frac{\pi}{3}-x\right)}{x}\right)$
$9x^2-40x+16=0$
$\sqrt[3]{6^{12}}$
$\left(r-8\right)\left(r-2\right)$
$\left(16x^2-28x+1\right)^2$
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