$\left(4x^3y+6\right)$
$\frac{3}{4}x^2-\frac{1}{8}x^2$
$\frac{dy}{dx}=-2\sin\left(x\right)$
$\lim_{x\to0}\:\left(4x^3-7x^2+4x-1\right)$
$2\cdot18$
$\left(2y\:-\:1\right)\left(2y\:-\:3\right)$
$\frac{x-5}{x^2-8x+12}$
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